How to assign tasks-rejoinder

This is with reference to my earlier blog regarding the assignment of 6 tasks to 6 persons
Task 2 can be assigned only to either person 3 or 4..
As task 1 cannot be assigned to either person 1 or 2,it could be assigned to either persons 3,5,6 or 4,5,6 depending on 4 or 3 being assigned task 2-So Tasks 1 and 2 can be assigned only in 6 ways viz 4/3,4/5,4/6,3/4,3/5,3/6.
The remaining 4 tasks can be assigned in 4! or 24 ways
Thus the total number of ways in assigning the 6 tasks is 6*24=144 ways.  

Nomination for liebster blog awards

Thank you,Aparna for nominating me for the liebster award.
The following are  the answers to your questions
1)I would like to see all teachers respected by their students
2)I was in need of help for having  a darshan in a temple and someone not known to me helped me by leading me with his hands.
3)My keen interest in mathematics
4)Variety is not confusing if looked at properly
5)We must avoid attending to some other job like speaking on phone etc
6)Thanking
7)To age without suffering any illness
8)Every person must readily help others needing it
9)Eat well,work well and forget all problems
10)Globalised  .
As per the procedures generally  followed I have nominated the following 5 persons for the Liebster Blog awards.-
1)rajirules.blogspot. in
2)mind your decisions.com/blog
3)bhargavbalakrishnan.blogspot.in
4)Insane by thoughts and human by living
5)http://anushankar.blogspot.in
I wish to raise the following questions-
1)What will you do if you are alone in a lonely island
2)What happens when an aircraft loses fuel
3)Can you find anything special about the word 'undergrounder'
4)Will you count zero as an odd or even number
5)Do you like astrology
6)Which sea is colder-Arctic or Antarctic
7)Can a day have more than 24 hrs
8)Out of geography,physics,mathematics or history which do you like most
9)Is it possible to have a meteorite crash without serious damage to persons,buildings etc
10)Out of the following which would you not like to miss-a music concert,a cricket match ,a tv serial or the uptodate news from media
I introduce myself as a honours graduate in physics ,now retired from several jobs including a stint in Libya,having interest in music,mathematics and acquaintance with words in english language.
I will be intimating the persons whom I have nominated to follow this up further by nominating  other bloggers known to them and communicate their responses to my questions-the first coming to their mind.

Movement of digits

 Consider the number shown below-
523814769
This number consists of each of the nine digits from 1 to 9 without any repetition and it is a perfect square..
You are required to convert it to 123456789 by movement of digits from one place to another by interchange.
For example by interchanging 5 and 6 from 523814769 you get 623814759.This is considered as one movement.
You are allowed 3 movements for conversion of 523814769 into 123456789.
Proceed.

Alphabet/number link

The following is an addition sum where each alphabet represents a distinct digit from among the 10 digits from 0 to 9-
    S  E  N  D
    M O  R  E
 -----------
M O N  E  Y
Find the actual addition sum as per those digits.

Filling up a sequence-two numbers to be filled up

Anybody willing to work out the next 2 numbers in the sequence below?-
7,7,2,4,3,3,4,3,7,2,3,?,?-
The answer is in the question itself.

Conversation with priest-Rejoinder

The organist could find the alternatives available for the values of ages where the product works out as 2450.As the sum of the ages was to be twice his own age and as he was unable to give the answer in the first instance,we can conclude his age as 32 and there were  2 alternatives available as (49,10,5) and (50,7,7) After the priest mentioned that he was the oldest,the organist could give answer.The logic works out as follows-If 'p' is the age of the priest and if p>50,he could not give the answer.If p<50,he could not be the oldest.So the organist concludes that p=50 and accordingly the ages of the visitors were 49, 10 and 5. 

One set of faulty coins

There are 10 sets of coins.You know how much the coins should weigh.You also know that all the coins in one set of 10 are exactly a hundredth of an ounce off,making that entire set of 10 coins a tenth of an ounce off.You are also told that all the other coins weigh the correct amount.You are allowed to use an extremely accurate digital weighing machine only once.How do you determine which set of 10 coins is faulty?