This is a rejoinder to my earlier blog of same title.
A correct reply has already been given by Shekar which may be seen under the comment portion.
The reply holds good if the weighing machine is capable to weigh correctly upto the weight of around 55 coins.Suppose it is capable to weigh correctly upto the weight of say around 45,46 etc of coins.In that case you must take no coins from one set,which you can mark.If all coins weigh correctly the total weight should be that of 45 coins,(45 being the sum of digits 1 to 9) and so the actual weight differring from weight of 45 coins will show you which set has the faulty coins.
A correct reply has already been given by Shekar which may be seen under the comment portion.
The reply holds good if the weighing machine is capable to weigh correctly upto the weight of around 55 coins.Suppose it is capable to weigh correctly upto the weight of say around 45,46 etc of coins.In that case you must take no coins from one set,which you can mark.If all coins weigh correctly the total weight should be that of 45 coins,(45 being the sum of digits 1 to 9) and so the actual weight differring from weight of 45 coins will show you which set has the faulty coins.
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